Answer:

Step-by-step explanation:
To find:
The value of
= ?
Solution:
Kindly consider the equilateral
as attached in the answer area.
Let the side of triangle =
units
Let us draw the perpendicular from vertex A to side BC.
It will divide the side BC in two equal parts.
i.e. BD = DC = 
Using Pythagorean Theorem in
:

Side AD = 
Using Trigonometric ratio:


Putting the values of AD and BD:

Answer:
32 mm²
Step-by-step explanation:
perimeter of left rectangle = 2(9 mm + 3 mm) = 24 mm
length of right rectangle = L
perimeter of right rectangle = 2(L + 4 mm) = 2L + 8
perimeter of right rectangle = 24 mm
The perimeter of the right triangle is 2L + 8 and also 24, so 2L + 8 must equal 24. We can solve for L and find the length of the right rectangle.
2L + 8 = 24
2L = 16
L = 8
area of right triangle = length × width
area = 8 mm × 4 mm
area = 32 mm²
Answer:
x = − 4y + 16
x = − 6y + 24
Step-by-step explanation:
Let's solve for x.
x + 4y = 16
Step 1: Add -4y to both sides.
x + 4y + − 4y = 16 + − 4y
x = − 4y + 16
Answer:
x = − 4y + 16
Let's solve for x.
2x + 12y = 48
Step 1: Add -12y to both sides.
2x + 12y + − 12y = 48 + − 12y/2x= − 12y + 48
Step 2: Divide both sides by 2.
2x/2 = − 12y + 48/2x = − 6y + 24
Answer: x = − 6y + 24
( I hope this was helpful) >;D
Answer:
The number of beads used must be at least 40 to make a decorated rope of at least 20 feet length. The inequality is:

Step-by-step explanation:
Let the number of beads used be 'n'.
Now, length of 1 bead = 6 in
∴ Length of 'n' beads = 
Now, minimum length of rope is 20 ft. Converting feet to inches, we get:

Now, beads are inserted in the rope. So, the length of rope is same as the length of all the beads joined together.
As per question, length must be at least 20 ft or 240 in.
Therefore, the length of all beads joined together must be at least 240 inches. This gives,

Therefore, the number of beads used must be at least 40 to make a decorated rope of at least 20 feet length.