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allochka39001 [22]
3 years ago
9

I’m not sure on what to do for these problems…can someone help me please

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

You need to find k, the constant of proportionality, by dividing y with its corresponding x.

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Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
3 years ago
f 4 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 81 beats per min
Darya [45]

Answer:

The answer is 0.9726

Step-by-step explanation:

7 0
3 years ago
Suppose Eric and Isaac both drive the same car, and have the same
Leto [7]

Answer:

eric

Step-by-step explanation:

just took the test

5 0
3 years ago
Read 2 more answers
Mrs. Polonsky has 19 students in her science class. Drag each ratio to the appropriate category.
antoniya [11.8K]

Answer:

Teachers to Students: 1:9, 1 to 19, 1/19

Students to teachers: 19:1, 19 to 1, 19/1

(If this is wrong the answers might be different for you but this is what I got an I was right)

4 0
2 years ago
Mark wants to improve his free throw percentage in basketball He has shot 1,250 free throws over the last 20 days. He shot eithe
Sedaia [141]
Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20

We also know that he shot total of 1250 shots:
50a + 100 b = 1250

We have two equations. We can solve them for a and b.  Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
50 * (20 - b ) + 100b = 1250
1000 - 50b + 100b = 1250
50b = 250
b = 5
a = 20 - 5
a = 15

Mark shot 100 shots on 5 days.
4 0
3 years ago
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