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miskamm [114]
3 years ago
6

Who want to play among us ​

Mathematics
2 answers:
sesenic [268]3 years ago
7 0
Yesssss i would love to because im so bored and i have to have 20 characters so thats y its so long
Ghella [55]3 years ago
4 0

Answer:me

Step-by-step explanation:

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  Can someone pleaseeee help if you’re correct I’ll give u brainlist
Ne4ueva [31]

Answer:

Just about 3.6

Step-by-step explanation:

a² + b² = c²

√(a² + b²) = c

√(2² + 3²) = c

√(4 + 9) = c

√(13) = c

3.605551275 = c

c ≈ 3.6

3 0
3 years ago
Read 2 more answers
Can you help me please I need it and this graduate
yanalaym [24]
Here is how to work the problems and write the expressions.

8 0
3 years ago
Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.
MakcuM [25]

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

               t_m=\frac{s}{50}=0.02s

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

               t_a=\frac{s}{40}=0.025s

Given that the return trip took 1/4hr longer because of traffic.

That is

             t_a-t_m=\frac{1}{4}hr=0.025hr

Substituting

             t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles

Distance to appointment point = 5 miles

7 0
3 years ago
Teloria, Maria, and Britt each ordered a pizza. Teloria ate
xxMikexx [17]
The Answer is D
Teloria- 32/56
Maria- 42/56
Britt- 35/56
7 0
3 years ago
Read 2 more answers
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
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