I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.
Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b. Now, it's shortened to be 56ab2-35.
Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.
I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.
So, that means the answer is 56ab2-35.
I hope this helps!! (And makes sense)
Remember, volume is length x width x height. (lxwxh)
5+3 inches is the apparent width. (8)
7+7 inches is the height. (14)
The length is seemingly difficult to solve, but it's easy when you get the hang of it.
You need to divide the toolbox into shapes you can find the volume for and then add it all together.
Let's take 14x5x(7+7). 980.
Now the other half. 16x3x(7+7). 672.
Add.
Volume is 1652 inches.
Answer:
The length and width of the parking lot are
meters and
meters, respectively.
Step-by-step explanation:
The surface formula (
) for the rectangular parking lot is represented by:

Where:
- Width of the rectangle, measured in meters.
- Length of the rectangle, measured in meters.
Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If
, the factorized form is:

Now, let consider that
and
, if
, the length and width of the parking lot are, respectively:




The length and width of the parking lot are
meters and
meters, respectively.
Answer:
then the perimeter of polygon B will also be twice of perimeter of polygon A
When we are to divide the line segment such that the ratio is 1:2, there are actually 3 parts of the segment. First, we determine the distance between the coordinates and divide the distance by 3. Then, we add the quotient to the x-coordinate.
x-coordinate: (2 - 9) / 3 = -7/3
y-coordinate: (6 - 3 ) / 3 = 1
Adding them to the coordinates of a,
x - coordinate: (9 - 7/3) = 20/3
y - coordinate: (3 + 1) = 4
Thus, the coordinates are (20/3, 4).