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Triss [41]
3 years ago
7

I need help. I can't figure this question out.

Mathematics
1 answer:
ki77a [65]3 years ago
4 0
  • -30a5b+12a4b3+16a3b2-4a2b4-2ab3
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David earned a gross pay of $160 for one week. He worked 20 hours. What is his hourly wage?
NikAS [45]

Answer:

8

Step-by-step explanation:

160 divided by 20 hours = 8.

David has a 8 hourly wage.

5 0
3 years ago
Read 2 more answers
What would 125 divided by 6 be?
kirza4 [7]

Answer:

20.8333333333

Step-by-step explanation:

Since 6 isn't a factor of 125 there will be a decimal.

6 goes into 125 20 times. Then it can fit in .8333333333 times.,

8 0
3 years ago
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David has scored 81 , 87 , 69 , and 82 on his previous four tests. what score does he need on his next test so that his average
kvv77 [185]
91 so the mean can avrege out to 82
7 0
3 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
How do you do this problem?
sertanlavr [38]

2x2x2 = 8

How many 2s are there?

3 so the answer is 3

4 0
3 years ago
Read 2 more answers
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