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olchik [2.2K]
3 years ago
6

Use one or more transformations to transform the pre-image (purple) onto the image (white).

Mathematics
1 answer:
kherson [118]3 years ago
5 0
Answer:

1. Dilate it to the same size as the white one
2. Rotate it until it is facing the same direction
3. Translate it on top of the white one as directed

Hope this helps!
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Divide (- 6 + i)/(1 - 2i) =
Kaylis [27]

~~~\dfrac{(-6 +i)}{(1- 2i)}\\\\\\=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{-6-12i+i+2i^2}{1-(2i)^2}\\\\\\=\dfrac{-6-11i-2}{1+4}~~~~~~~~~~~~~;[i^2=-1]\\\\\\=\dfrac{-8-11i}{5}\\\\\\=-\dfrac 85-\dfrac{11}{5}i

4 0
1 year ago
Read 2 more answers
-4.8f+6.4=-8.48 what's f 7.3y-5.18=-51.9 what's y
stich3 [128]
F=4 and y=3 those are the answers
8 0
3 years ago
Point T(-9,5) lies on the perpendicular bisector of UV. If the
Flura [38]

The coordinate of point V is at (-16, 9)

If Point T(-9,5) lies on the perpendicular bisector of UV, this means that the point divides the line UV into two equal parts

Given the following coordinates

Midpoint T = (-9, 5)

U = (-2, 1)

Required

coordinate of point V

Using the midpoint formulas;

T(x, y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\T(-9, 5) = (\frac{-2+x_2}{2}, \frac{1+y_2}{2})

Get the value if x₂ and y₂

-9 = \frac{-2+x_2}{2}\\-18 = -2+x_2\\x_2 = -18+2\\x_2 = -16\\

Similarly;

5 = \frac{1+y_2}{2}\\10 = 1+y_2\\y_2 = 10-1\\y_2 = 9\\

Hence the coordinate of point V is at (-16, 9)

Learn more here: brainly.com/question/18049211

5 0
3 years ago
In which section of the number line is √5?
Ymorist [56]

We know that \sqrt(4) and \sqrt(9) are 2 and 3 respectively. Therefore, /sqrt(5) is between 2 and 3, approximately 2.2.

6 0
3 years ago
Pls answer quick I will give bainlyest to first GOOD answer
Helen [10]

Answer:

R1 - given

R2 - subtraction property of equality

R3 - distribution

S4 - 9x = 61

R5 - division prop. of equality

Step-by-step explanation:

hope this helps :)

5 0
3 years ago
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