Question

Find the length of AC.a. 10.1 b. 10.0c. 10.9d. 8.86 PLEASE HELPPP ASAP ​

Answer 1

Answer:

Option D

Step-by-step explanation:

According to law of cosines =

${a}^{2} = {b}^{2} + {c}^{2} - 2bc. \cos(A)$

where 'a' is the uknown side , 'b' & 'c' are the given sides and angleA is the angle opposite to the uknown side i.e. opposite to 'a'.

Using the Law of cosines , we'll find the length of AC .

${ac}^{2} = {7}^{2} + {13}^{2} - 2 \times 7 \times 13 \times \cos(50)$

$= > {ac}^{2} = 49 + 169 - 182 \times 0.76$

$= > {ac}^{2} = 218 - 138.8 = 79.68$

$= > ac = \sqrt{79.68} = 8.92 = 9(appx)$

In option D , if we'll round of 8.86 , then its appx 9. So option D is right