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dybincka [34]
2 years ago
5

GIVING BRAINLIEST TO WHOEVER ANSWERS THIS QUESTION CORRECT

Mathematics
1 answer:
Yakvenalex [24]2 years ago
4 0

Answer:

  • No correct choice

Step-by-step explanation:

<u>Given</u>

  • r = 23 in

<u>Area of the mirror:</u>

  • A = πr²
  • A = 3.14*23² = 1661 in²

None of the choices is correct

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Find the values of the variables for which ABCD must be a parallelogram
sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0
3 years ago
Karen has 7 over 8cup of ice cream. How many 1 over 3cup servings can she make?
AlexFokin [52]
First, we need to find the least common denominator. The LCD for 7/8 and 1/3 would be 24. 7*3/8*3 = 21/24. 1*8/3*8 = 8/24. So, how many 8/24 will go into 21/24? 8 goes into 21 two times, and we are left with a remainder of 5. The answer is: Karen can make 2 and 1/24 servings of 1/3 cups of ice cream.
3 0
3 years ago
Read 2 more answers
Write an equation for a circle with center at (5,-2) and diameter of 8 centimeters.
mars1129 [50]

Answer:

(x-5)^2+(y+2)^2=16

Step-by-step explanation:

lol brainlessly...

General Circle function: (x-h)^2+(y-k)^2=r^2, where h is the x-coordinate of the center, k is the y-coordinate of the center, and r is the radius.

The radius of the circle is half the diameter so: 8 / 2 = 4

The x-coordinate of the circle is 5

The y-coordinate of the circle is -2

Plug in.

(x-5)^2+(y-(-2))^2=4^2

(x-5)^2+(y+2)^2=16

5 0
3 years ago
What is the difference between domain and range?
alekssr [168]

Domain: all x values between the ends of a line on the x- axis

Range: all y values between the ends of a line on the y-axis

4 0
3 years ago
Write an equation (any form) for the quadratic graphed below. Y=
Licemer1 [7]

Answer:

y = -2x^2 - 4x - 1

Step-by-step explanation:

We can see that the graph passes through (-2, -1), (-1, 1) and (0, -1).

Let's solve

ax^2 + bx + c = y

a(-2)^2 + b(-2) + c = -1

4a - 2b + c = -1

a(-1)^2 + b(-1) + c = 1

a - b + c = 1

a0^2 + b0 + c = -1

c = -1

we got c = -1 so we input it into the other 2

4a - 2b - 1 = -1

4a - 2b = 0

2a - b = 0

2a = b

a - b - 1 = 1

a - b = 2

a = b + 2

Let's input b = 2a

a = 2a + 2

-a = 2

a = -2

b = 2a = 2*(-2) = -4

c = -1

y = -2x^2 - 4x - 1

4 0
3 years ago
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