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3 years ago

GIVING BRAINLIEST TO WHOEVER ANSWERS THIS QUESTION CORRECT

Mathematics

1 answer:

Yakvenalex [24]3 years ago

4 0

Answer:

No correct choice

Step-by-step explanation:

<u>Given</u>

r = 23 in

<u>Area of the mirror:</u>

A = πr²
A = 3.14*23² = 1661 in²

None of the choices is correct

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Write the standard form of the line that contains a y-intercept of -3 and passes through the point (3, 0). Include your work in

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(3,0) (0,-3)

slope: -3-0/0-3

-3/-3

m=1
b=-3

y=x-3
-x -x

-x+y=-3

-1(-x+y=-3)

x-y=3

There's a possiblity that I'm wrong. It's been a while since I've done this.

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Answer:

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IgorC [24]

Answer:

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Please help if you can!

Stolb23 [73]

Answer:

Step-by-step explanation:

f(6) = -6

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Now, we can plug in these values!

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3 years ago

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If t a n squared θ = 3 /8 , what is the value of s e c θ

TEA [102]

We can use 3 facts:

$\tan{\theta}=\frac{y}{x}$

$\sec{\theta}=\frac{r}{x}$

$x^2+y^2=r^2$

So, to find our x and our y we can do:

$\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}$ So, now that we know our x and our y we can find our r.

$(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}$

You'll notice, though, that there were two solutions for $\tan{\theta}$ , which means we have a positive and a negative for our x. So:

$\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}$

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3 years ago

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