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2 years ago

14

(4) |-5 + (-2)| _____ |5 + 2| < > =

2 answers:

nikitadnepr [17]2 years ago

4 0

Hi

The answer would be =

Why?

The `| |` symbols mean actual value, which makes every number inside of it positive. That would mean, following the rules of actual value, the equation would look like:

5 + 2 _____ 5 + 2

Both add up to 10, so both equations are equal.

lutik1710 [3]2 years ago

4 0

Answer:

>

Step-by-step explanation:

(4)| -5 + (-2)| ____ |5 + 2|

(4)| -7| ____ |7|

(4)(7) ____ 7

28 > 7

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What is the slope of the line represented by the equation 2x+3y= –12 ? –32 –23 23 32

mr_godi [17]

Answer:

Option 2 - $m=-\frac{2}{3}$ is the slope of the equation.

Step-by-step explanation:

Given : Equation $2x+3y=-12$

To find : What is the slope of the line represented by the equation ?

Solution :

The slope form of line is $y=mx+c$

Equation $2x+3y=-12$

Take 2x to another side,

$3y=-12-2x$

Divide 3 both side,

$y=\frac{-12-2x}{3}$

$y=\frac{-2}{3}x-4$

On comparing with general equation,

$m=-\frac{2}{3}$ is the slope of the equation.

Therefore, option 2 is correct.

7 0

2 years ago

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The half-life of a radioactive element is 130 days, but your sample will not be useful to you after 80% of the radioactive nu

gtnhenbr [62]

Answer:

We can use the sample about 42 days.

Step-by-step explanation:

Decay Equation:

$\frac{dN}{dt}\propto -N$

$\Rightarrow \frac{dN}{dt} =-\lambda N$

$\Rightarrow \frac{dN}{N} =-\lambda dt$

Integrating both sides

$\int \frac{dN}{N} =\int\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$\Rightarrow ln|N_0|=-\lambda .0+c$

$\Rightarrow c= ln|N_0|$

$\therefore ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$ .......(1)

$\frac{N}{N_0}=e^{-\lambda t}$ .........(2)

Logarithm:

$ln|\frac mn|= ln|m|-ln|n|$
$ln|ab|=ln|a|+ln|b|$

$ln|e^a|=a$

$ln|a|=b \Rightarrow a=e^b$
$ln|1|=0$

130 days is the half-life of the given radioactive element.

For half life,

$N=\frac12 N_0$ , $t=t_\frac12=130$ days.

we plug all values in equation (1)

$ln|\frac{\frac12N_0}{N_0}|=-\lambda \times 130$

$\rightarrow ln|\frac{\frac12}{1}|=-\lambda \times 130$

$\rightarrow ln|1|-ln|2|-ln|1|=-\lambda \times 130$

$\rightarrow -ln|2|=-\lambda \times 130$

$\rightarrow \lambda= \frac{-ln|2|}{-130}$

$\rightarrow \lambda= \frac{ln|2|}{130}$

We need to find the time when the sample remains 80% of its original.

$N=\frac{80}{100}N_0$

$\therefore ln|{\frac{\frac {80}{100}N_0}{N_0}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{\frac {80}{100}|=-\frac{ln2}{130}t$

$\Rightarrow ln|{{ {80}|-ln|{100}|=-\frac{ln2}{130}t$

$\Rightarrow t=\frac{ln|80|-ln|100|}{-\frac{ln|2|}{130}}$

$\Rightarrow t=\frac{(ln|80|-ln|100|)\times 130}{-{ln|2|}}$

$\Rightarrow t\approx 42$

We can use the sample about 42 days.

7 0

3 years ago

What is £900 decreased by 5%

zaharov [31]

First find out what 5% of 900 is.

0.05 * 900 = 45

Now subtract this from 900.

900 - 45 = 855

So £900 decreased by 5% is £855.

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3 years ago

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Which is cheaper per deal A) $63 for an 18-issue subscription B) $72 for an 24-issue subscription

Alenkinab [10]

B) because a you pay less and get less b you get more and pay more

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2 years ago

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3. Anya budgets $194 for commuting to

Anon25 [30]

Answer:

c

Step-by-step explanation:

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