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juin [17]
3 years ago
8

Is -2/3(12b - 6 + 9b - 18) equivalent to 2b(b + 8)? Show your work.

Mathematics
2 answers:
AURORKA [14]3 years ago
8 0

Answer:

No, they are not equivalent

Step-by-step explanation:

\frac{-2}{3}(12b - 6 + 9b - 18) = \frac{-2}{3}(12b + 9b - 6 - 18)\\\\=\frac{-2}{3}(21b - 24)\\\\  = \frac{-2}{3}*21b -24*\frac{-2}{3}\\\\= -2*7b + 8*2\\\\= 2( -7b + 8)

masha68 [24]3 years ago
4 0

Answer:

This is NOT equivalent to 2b(b + 8).

Step-by-step explanation:

Start with -2/3(12b - 6 + 9b - 18).  Simplify this.  First, combine the like terms inside the set of parentheses:

(-2/3)(21b - 24)

Simplify this by applying the distributation property of multiplication:

-14b + 16

Finally, factor out 2:  2(-7b + 8)

This is NOT equivalent to 2b(b + 8).

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Write the slope intercept form of each equation of the line. Use a fraction for slope if needed.
zhuklara [117]

Answer:

y=-x+6

Step-by-step explanation:

Start by graphing y=-x+5.  Then mark the point (2,4) for easier reference.  A parallel line just has the same slope, so if you make another line with the same slope, and change the y-intercept until the line goes through (2,4), you will have the answer.

8 0
2 years ago
What is |-8|? I really need help ​
velikii [3]

Answer:

8 is the correct answer

8 0
3 years ago
11. Find the exact value by using a half-angle identity. (1 point)
ValentinkaMS [17]
<span>11. Find the exact value by using a half-angle identity. 
</span><span>sin (22.5)
</span><span>the sine half-angle formula
</span>

sin<span>(x/2)</span>=±((1−cos(x))/2) ^0.5         cos 45=(2^0.5)/2

sin(22.5)=±((1−cos(45))/2) ^0.5

sin(22.5)=±((2-2^0.5))^0.5/2

sin(22.5)=±0.3826834324

<span>
12. Find all solutions to the equation in the interval [0, 2π)
</span>cos x = sin 2x
cosx-sin 2x=0
<span>using a graphical tool
</span>in the interval [0, 2π)

<span>the solutions are
x1=0----------------not solution
x2=</span>π/6------------ not solution<span>
x3=</span>π/2------------ is a solution<span>
x4=5</span>π/6---------- not solution<span>
x5=3</span>π/2---------- is a solution

<span>the answer is the letter <span>a) pi divided by two. , three pi divided by two

</span></span>

13. Rewrite with only sin x and cos x. sin(2x) = 2*sin(x)*cos(x)

sin 2x - cos x=2*sin(x)*cos(x)- cos x= cos x*(2*sin(x)-1)

<span>the answer is  the letter <span>c) cos x (2 sin x - 1)

</span></span>

<span>14. Verify the identity. 
cosine of x divided by quantity one plus sine of x plus quantity one plus sine of x divided by cosine of x equals two times secant of x</span>.

cosx/(1+sinx) + (1+sinx)/cosx 

<span>
= (cosx * cosx + (1+sinx)(1+sinx)) / (cosx (1+sinx)) 
= (cos²x + sin²x + 2 sinx + 1) / (cosx (1+sinx)) 
= (1 + 2 sinx + 1) / (cosx (1+sinx)) 
= (2 + 2 sinx) / (cosx (1+sinx)) 
= 2 (1+sinx) / (cosx (1+sinx)) 
= 2/cosx 
<span>= 2 secx  Ok is correct</span></span>

6 0
3 years ago
The 2nd term in a geometic sequence is 20. the fourth term in the same sequence is 45/4 or 11.25. what is the common ratio in th
Over [174]
Let x be the value of the third term.
Since it's a geometric sequence, then:
Third term/Second term = Fourth term/Third term
x/20 = 11.25/x
Cross multiplication:
x^2 = 225
x = 15
So since the ratio is constant, then it is
x/20 = 15/20 = 3/4
So the common ratio is 3/4 or 0.75.
8 0
3 years ago
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