There are 62 dimes and 44 nickels.
N + D = 106 (There are 106 coins in all.)
1 nickel = 5 cents.
1 dime = 10 cents.
5*N + 10*D = 840 ($8.40 = 840 cents)
N + D = 106 -------(1)
N = (106 - D)
5*N + 10*D = 840 ---------(2)
5*(106-D) + 10*D = 840
530 - 5*D + 10*D = 840
5*D = 840 - 530
5*D = 310
D = 310/5 = 62
Eq(1) N + D = 106
N + 62 = 106
N = 106 - 62
N = 44
Answer:
<h2> $1945</h2>
Step-by-step explanation:
Let X be the normal distribution
Kindly find attached a detailed annotation of the solution to the problem.
in the attached document, we found the value that corresponds to 80th percentile, hence we found the value such that the probability that the variable x is lower than this value is 0.8.
Also, from the calculation, we found that the value which corresponds to the 80th percentile is $1945
Answer:15
Step-by-step explanation:
It’s the last one & the second one