A work out the value of 1^2+2^3+3^4 b work out the value of 4^2 x 2^4

Mathematics

2 answers:

bija089 [108]3 years ago

8 0

Answer:

Below in bold.

Step-by-step explanation:

Use order of operations: the exponents are calculated first, then multiplication, then addition.

a. 1^2+2^3+3^4

= 1 + 8 + 81

= 90.

b. 4^2 * 2^4

= 16 * 16

= 256.

IgorLugansk [536]3 years ago

7 0

Answer:

90 and 256.

Step-by-step explanation:

1^2 + 2^3 + 3^4

Solve for the powers or exponents first.

1 + 8 + 81

Add the numbers.

= 90

4^2 × 2^4

Solve for the powers or exponents first.

16 × 16

Multiply the numbers.

16^2

= 256

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Someone ask me to solve this.

Semenov [28]

X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .

6 0

3 years ago

Last season, your

Katarina [22]

Answer:

55%

Step-by-step explanation:

The percent change formula is written like this:

$|\frac{change - original }{original}|$ . In this scenario, the "change" or new value is 31, because it is this season, and the original is last season. Now, 31-20 = 11, and 11/20 = 55%.