Elijah buys a one-pint bottle of juice for $2.88. What is the unit rate of the cost of the juice per fluid ounce?

Mathematics

1 answer:

mojhsa [17]3 years ago

3 0

Answer: 0.48
Explanation: $2.88 / 16

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Thereare 30 students in mr.holland's music class.if 30% of the students play in the school band,how many students in the class p

stiv31 [10]

9 students in the class play in the school band.

30% of 30
Well, when doing a percentage you first turn the percentage into a decimal (move the % two units to the left). So 30% = 0.3

In math, the word of means multiplication, so: 0.3 x 30
Which equal 9.

You can also turn the percentage into a fraction, it's really up to preference.

30/100 of 30 = 3/10 of 30 = 3/10 x 30 = 3/10 x 30/1 = 9/1 or 9

6 0

3 years ago

Read 2 more answers

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$