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rosijanka [135]
2 years ago
12

Look at the square pyramid shown below. Which of the equation best represents volume of this pyramid terms of H?

Mathematics
1 answer:
UkoKoshka [18]2 years ago
8 0

Answer:

J. V = 12h cubic units

Step-by-step explanation:

Volume if a square pyramid = ⅓*a²*h

Where,

h = height = ?

a = edge = 6 in.

Plug in the values

Volume = ⅓*6²*h

V = ⅓*36*h

V = 12*h

V = 12h cubic units

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5d-2/3c if d =4 and c =3 evaluate fast fast
Mademuasel [1]

Answer:

2

Step-by-step explanation:

Plug 4 in for d and 3 in for c

5d-2/3c

5(4)-2/3(3)

Multiply in the numerator and the denominator

20-2/9

Subtract in the numerator

18/9

2

Hope this helps! :)

4 0
3 years ago
Write the equation of the line in point-slope form of the given point and slope. This is an essay style question. If you hit the
svp [43]

Answer:

<h3>y + 2 = 3/7(x-7)</h3>

Step-by-step explanation:

The point-slope form of the equation will be expressed as;

y - y0 = m(x-x0) where;

m is the slope

(x0, y0) is the point on the line

Given

Slope m = 3/7

Point (x0, y0) = (7, -2)

Substitute into the equation;

y - y0 = m(x-x0)

y - (-2) = 3/7 (x - 7)

<em>y + 2 = 3/7(x-7)</em>

<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>

3 0
3 years ago
Pls answer pls ok ok ok ok o ok
cestrela7 [59]

Answer: a

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help on this.
tiny-mole [99]

Step-by-step explanation:

Given

22m - 33 = 11( 2m) - 11(3)

= 11 ( 2m - 3 )

Hope it helps :)

3 0
3 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
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