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3 years ago

GIVING BRAINLIEST PLS HELP (x + 3)^2 – 3 = 0 lesser x = greater x=

Mathematics

2 answers:

agasfer [191]3 years ago

7 0

Answer:

(x+3)^2 -3 =0 then

$\sqrt{(x + 3 ){}^{2} } = - or + \sqrt{3} \\ x + 3 = - or + \sqrt{3} \\ x = - or + \sqrt{3} - 3$

lesser of x is

$- \sqrt{3} - 3and \\ greate \: of \: x = \sqrt{3} - 3$

malfutka [58]3 years ago

4 0

^ I got same thing as above

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Please help. Khan sucks!

Llana [10]

Answer:

Your answer is

3z=30

z=10.

7 0

2 years ago

Read 2 more answers

In a survey of 155155 senior executives, 48.448.4% said that the most common job interview mistake is to have little or no kno

victus00 [196]

Answer:

We conclude that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Step-by-step explanation:

We are given that in a survey of 155 senior executives, 48.4% said that the most common job interview mistake is to have little or no knowledge of the company.

We have to use a 0.05 significance level to test the claim that in the population of all senior executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Let p = population proportion of senior executives who said that the most common job interview mistake is to have little or no knowledge of the company

So, Null Hypothesis, $H_0$ : p = 40% {means that in the population of all senior executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company}

Alternate Hypothesis, $H_A$ : p $\neq$ 40% {means that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of senior executives who said that the most common job interview mistake is to have little or no knowledge of the company = 48.4%

n = sample of senior executives = 155

So, the test statistics = $\frac{0.484-0.40}{\sqrt{\frac{0.484(1-0.484)}{155} } }$

= 2.09

The value of z test statistics is 2.09.

Also, P-value of the test statistics is given by;

P-value = P(Z > 2.09) = 1 - P(Z $\leq$ 2.09)

= 1 - 0.9817 = 0.0183

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company.

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4 years ago

Create and solve equations, showing your work. You must create the equations and show the steps required to solve them.

jok3333 [9.3K]

One step equation, where only one step is required to solve the problem. Example:
20 = 5x
4 = x

Fractions:
1/2 + x = 3/2
x = 3/2 - 1/2
x = 1

Decimals:
0.5 + x = 1.5
x = 1.5 - 0.5
x = 1

Real world problem: (word problem and equation)
It costs $5 per hour to rent a canoe plus a $3 rental fee. How much will the total be if you plan on renting the canoe for 3 hours?
y = 5x + 3
y = total cost ; x = number of hours rented
y = 5×3 + 3
y = 15 + 3
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4 years ago

One astronomical unit is about 93,000,000 miles. At 20,000 miles per hour, how many astronomical units can Orion travel in one h

Olenka [21]

Answer:

$\frac{1}{4,650}\ astronomical\ unit$

$2.15*10^{-4}\ astronomical\ unit$

Step-by-step explanation:

we know that

One astronomical unit is about 93,000,000 miles

using proportion

Find out how many astronomical unit represent 20,000 miles

Let

x ----> the number of astronomical unit

$\frac{1}{93,000,000} =\frac{x}{20,000}\\\\x=\frac{20,000}{93,000,000}\ astronomical\ unit$

simplify

$\frac{1}{4,650}\ astronomical\ unit$

$2.15*10^{-4}\ astronomical\ unit$

3 0

3 years ago

Read 2 more answers

Sila jogged 12 kilometers today and wants to know how far she traveled in feet. What error did Sila make while converting from k

Savatey [412]

Answer:

Sila put a wrong number in her calculator when multiplying the numerators.

Step-by-step explanation:

StartFraction 12 kilometers Over 1 EndFraction times StartFraction 0.62 miles Over 1 kilometer EndFraction times StartFraction 5280 feet Over 1 mile EndFraction = 392,832 feet

Correct calculation:

12 km/ 1 * 0.6miles / 1km * 5280 feet / 1 mile

= (12km * 0.62 miles * 5280 feet) / (1 * 1 km * 1 mile)

= 39,283.2 feet

Sila's calculation:

12 km/ 1 * 0.6miles / 1km * 5280 feet / 1 mile

= 392,832 feet

3 0

3 years ago