Lets think they have cards, Alex = x , Gil = y and Meg = z. Then,
x+y+z = 740
Alex had 20 fewer cards than Gil. So,
x+20 = y
Alex had 120 fewer cards than Meg. So,
x+120 = z
x+(x+20)+(x+120) = 740
3x + 140 = 740
x= 200
y= 220
z= 320
<span>So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards</span>
A. No
5 + 15 = 20
B. Yes
33/3 (33 ÷ 3) = 11
C. No
5 × 7 = 35
Answer:
0
Step-by-step explanation:
Assuming the six sided dice are numbered 1 through six
The max each could roll is 6
6+6 = 12
They cannot reach a sum of 13
Set up a proportion.
Let x = the number of students in 29970 who speak 3 or more languages.
285/19 = 29970/x Cross multiply
285 x = 19 * 29970
285x = 569430
x = 569430/285
x = 5415 students speak 3 languages.
