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Mars2501 [29]
3 years ago
15

Write the rate and unit rate for each phrase given below.

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0
1) 80 inches of snow over 10 days
Rate: 80 inches of snow over 10 days
Unit rate: 8 inches of snow per day

2) 3 comic books for 3 dollars
Rate: 3 comic books for 3 dollars
Unit rate: $1 per comic book

3.) 5 pounds of potatoes cost $10
Rate: 5 pounds of potatoes cost $10
Unit rate: $2 for every pound of potatoes

Have a nice day!
-SpaceMarsh
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Anna35 [415]
The answer to this is D!!!!
8 0
3 years ago
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Apply Gaussian quadrature with n = 4 to approximate integrate sin x^2dx from 1 to 5
maks197457 [2]
First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx
x=1\implies t=\dfrac{2-6}4=-1
x=5\implies t=\dfrac{10-6}4=1

So,

\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt

Let f(t)=2\sin(2t+3)^2. With n=4, we're looking for coefficients c_i and nodes x_i, with 1\le i\le4, such that

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)
\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790
4 0
3 years ago
X/3 - 11 = -2 <br> the answer i got was 27, but it’s suppose to be 21. how do i get there?
yawa3891 [41]

Answer: x = 27

Step-by-step explanation:

x/3 - 11 = -2

Add 11 to each side

x/3 = 9

Multiply each side by 3

x = 27

x cannot equal 21.

21/3 - 11

21/3 = 7

7 - 11 = -4

-4 does not equal -2

Therefore, x cannot equal 21.

7 0
3 years ago
6th grade math help me pleaseeee
azamat

Answer:

The 1st one

Step-by-step explanation:

3 0
3 years ago
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A choir is performing in front of an audience. a microphone is placed in front of the choir to capture sound. which polar equati
viktelen [127]

The polar equation is r = 2 + cos(theta).

Given,

A choir is performing in front of an audience. a microphone is placed in front of the choir to capture sound.

The polar equation represents the microphone the choir is using i.e

On edge i.e r = 2 + cos(theta)

Hence, The polar equation is r = 2 + cos(theta).

Learn more about polar equations here brainly.com/question/23575937

#SPJ4

3 0
2 years ago
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