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BaLLatris [955]
3 years ago
13

Please really need help on this please

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0
0,1 0,7 I think I use to do these
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WILL GIVE BRAINLIST SOON AS I CAN SOMEBODY PLEASE HELP ME ​
fgiga [73]

Answer:

A= 75.06 Sq Cm

Step-by-step explanation:

Please refer to the picture attached with this.

In ΔABD

AB = 8.5 , AD = 6 and say BD = x

Applying Pythagoras theorem in this triangle

Pythagoras theorem says

a^2+b^2=c^{2}

where c is the side opposite to the right angle, and b and a are the other two sides of the right angled triangle.

x^2+6^2=8.5^{2}

x^2=72.25-36

x^2=36.25

x=6.02

Hence side a = x +19

a = 6.02+19

a = 25.02

Now we apply the formula for area of a triangle which is given as

A=\frac{1}{2}\times b \times h

Where b is the base , here we have base as a = 25.02

h is the height , here h = 6

Putting these values in Formula we get

A=\frac{1}{2}\times 25.02 \times 6

A= 25.02 \times 3

A=75.06

Hence Area of the triangle is 75.06 sq cm

5 0
3 years ago
Simplify #53: 3(x + 2) - 4x<br><br><br><br> Help please
labwork [276]

Answer:

-x+6

Step-by-step explanation:

3(x+2)-4x

3x+6-4x

-x+6

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2 years ago
Factor.<br> 22 – 7x - 30
polet [3.4K]

-8 - 7x is the factored version.

7 0
3 years ago
Read 2 more answers
A dealer paid $7,000 for a car at an auction. At the dealership, a salesperson sold the car for 30% more than the auction price.
timurjin [86]
30% of $7000 is $2100
25% of $2100 is $525
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3 years ago
Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
Serggg [28]

{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}

\small\color{blak}{{\underline{\bold{ Find \:a X } } }  }

\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } }  } \\  = 173 = 25x - 2 \\  =  - 25x =  - 2 - 173 \\  =  - 25x - 175 \\  = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}

\small\color{blak}{{\underline{\bold{ Find\:a\:m

\small\color{blak}{{\underline{\bold{ 10(7)-2 } } }  }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m

\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}

7 0
3 years ago
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