Answer:
isSquare = true;
for (int i = 0; i < a2d.length && isSquare; i++)
if (a2d[i].length != a2d.length)
isSquare = false;
Explanation:
Answer:
-32 to +31
Explanation:
6 bit 2s complement representation will be of the form b1b2b3b4b5b6 where each bit is either 0 or 1.
The largest positive number that can be represented using this scheme is 011111
Translating this to decimal this is 1*2^4 + 1^2^3 + 1^2^2 + 1^2^1 + 1^2^0
=16 + 8 + 4 + 2 + 1 =31
The smallest negative number that can be represented using this scheme is 100000
Translating this to decimal = -1 * 2^5 = -32
So the range of decimal values that can be represented is -32 to +31.
Answer: I think it's D.
Explanation: I'm sorry if I chose the wrong answer, I'm not too good with stuff like this.
Use proper words. Also, add interesting facts about the subject
7 1/6
43 goes into 6 7 times with one left over. 6x7= 42 43-42=1
7 1/6
