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blsea [12.9K]
3 years ago
14

System uses a 6-bit 2’s complement signed integer representation. What is the range of decimal values it can represent?

Computers and Technology
1 answer:
kap26 [50]3 years ago
6 0

Answer:

-32 to +31

Explanation:

6 bit 2s complement representation will be of the form b1b2b3b4b5b6 where each bit is either 0 or 1.

The largest positive number that can be represented using this scheme is 011111

Translating this to decimal this is 1*2^4 + 1^2^3 + 1^2^2 + 1^2^1 + 1^2^0

=16 + 8 + 4 + 2 + 1 =31

The smallest negative number that can be represented using this scheme is 100000

Translating this to decimal = -1 * 2^5 = -32

So the range of decimal values that can be represented is -32 to +31.

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Kevin would like to ensure that his software runs on a platform that is able to expand and contract as needs change. Which one o
Reil [10]

A terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is: A. Scalability.

<h3>What is scalability?</h3>

Scalability can be defined as a measure of the ability of a system to change (expansion or contraction) in performance and cost as a result of changes in demands of application and system processing, especially in a network architecture.

In this context, we can logically deduce that a terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is scalability.

Read more on scalability here: brainly.com/question/14301721

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Complete Question:

Kevin would like to ensure that his software runs on a platform that is able to expand and contract as needs change.  Which one of the following terms best describes his goal? A. Scalability B. Elasticity C. Cost effectiveness D. Agility

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1 year ago
A previously saved labels report can be accessed from the
Tcecarenko [31]

C. is the answer to that question

6 0
3 years ago
US-CERT is a set of moderated mailing lists full of detailed, full-disclosure discussions and announcements about computer secur
n200080 [17]

Answer:

False

Explanation:

BugTraq is a high volume, full disclosure mailing list for the detailed discussion and announcement of computer security vulnerabilities, not US-CERT

3 0
2 years ago
This is gonna be very long but I have no idea what to do, I'm confused.
kaheart [24]

for such experiment, you do it with care and to acquire and determine to put experience in it

Explanation:

because without you been or using experience the experiment will not correct

8 0
2 years ago
You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
2 years ago
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