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Hunter-Best [27]
3 years ago
12

A water chips system in a garden uses 2/3 cup of water every 1/6 of an hour how much water is used one hour

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0

Answer:

4

Step-by-step explanation:

1/6 of an hour is 10 minutes. there are 60 minutes. 2/3 times 6 is 4. I hope that helped :)

Lubov Fominskaja [6]3 years ago
4 0

Answer:

6*2/3= 4 cups of water are used in one hour

Step-by-step explanation:

There is 6, 1/6 of an hour in an hour so we would multiply 2/3 (which is used every 1/6 of an hour) by 6 to get the answer.

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If we break down the problem if basically gives the answer:
five times the quotient of some number and ten
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A

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Substitue 15 into the x value and complete the equation.

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If NS bisects QNR find the measure of QNR
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both angles would equal the same so you have:

6x-57 = 2x+15

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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

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  • 4 blue balls

  • 6 yellow balls

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<h3>1. what is the probability that the ball chosen is red ?</h3>

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\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

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