There are 36 combinations, 5 combinations equal 8
(2,6) (3,5) (4,4) (5,3) (6,2) all equal 8
The chance of rolling 8 is 5/36 (combinations that equal 8/total combinations)
5/36=.13888...
Answer:
Step-by-step explanation:
6/9+x=7/10
x=7/10-6/9
when adding fractions both denominators must be equal, we’ll make them 90
x=(7/10)(9/9)-(6/9)(10/10)
x=63/90-60/90
x=3/90, the greatest divisor of 3 and 90 is 3 so divide both the numerator and denominator by 3
x=(3/3)/(90/3)
x=1/30
Answer:
x = 1 - 5t
y = t
z = 1 - 5t
Step-by-step explanation:
For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).
Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.
We have x = e^(-5t)cos5t
at t = 1, x = e^(-5)cos5
at t = 0, x = 1
y = e^(-5t)sin5t
at t = 1, y = e^(-5)sin5
at t = 0, y = 0
z = e^(-5t)
at t = 1, z = e^(-5)
at t = 0, z = 1
Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.
In vector notation, the curve
r(t) = xi + yj + zk
= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k
r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k
r'(0) = -5i + j - 5k
is a vector tangent at the point.
We get the parametric equation from this.
x = x(0) + tx'(0)
= 1 - 5t
y = y(0) + ty'(0)
= t
z = z(0) + tz'(0)
= 1 - 5t
Answer:
2x^2+9x-5
Step-by-step explanation:
(X+5)(x-1/2)
x^2-1/2x+5x-5/2
x^2+9/2x-5/2
multiply through by 2
2x^2+9x-5
AWSER is C
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