(f+g)(x)=f(x)+g(x)=(2x-6)+(4x+7)=6x+1
(f-g)(x)=f(x)-g(x)=(2x-6)-(4x+7)=-2x-13
(fg)(x)=f(x)×g(x)=(2x-6)(4x+7)=8x^2-10x-42
(f+g)(-2)=f(-2)+g(-2)=(2(-2)-6)+(4(-2)+7)=-11
I guess I can give a brief overview and then you can decide if I should go deeper into these meaning and use.
Complex numbers are useful because in a lot of cases we need to use the square root of a negative number. Ex.
Solve the quadratic equation x^2+x+1=0
We have to use the quadratic formula since its not factorable.
x=[-1+-sqrt(1-4*1*1)]/2
x=-1/2 + or - sqrt(-3)
If we don't have imaginary numbers, we would be stuck because sqrt(-3) wouldn't exist as you cannot take the square root of a negative number.
But with complex numbers we can actually get the answer for that equation as
x=-1/2 + or - sqrt3*i
Which would give us a mean of using this answer to calculate further to get other needs depending on the problem you are solving. If complex number is not a thing, about half of our equations will have undefined answers.
Now conjugates is a more interesting one, on the surface level we are discussing here there is not much its used for except if you have a complex number as a root of a quadratic equation, then the conjugate of that complex number must also be a solution. Again if you want me to go a more in depth just comment down below, because I could write an entire essay on this topic :-)
Answer:
The last one
Step-by-step explanation:
Due to there being xy's in both terms
Answer:
D. -(-2/9)
Step-by-step explanation:
Once you distribute the negative sign, it makes the same answer.
-2 times -1 = 2
9 times -1 = -9
2/-9
I am pretty sure the answer is 3.5.
(2+x)5=11
(2+x)=11/5
(2+x)= 5.5
x= 5.5-2
x= 3.5