Proportional or non-proportional
1 answer:
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Answer:
And the best option would be:
c. 1450 +/- 12
Step-by-step explanation:
Information provided
represent the sample mean for the SAT scores
population mean (variable of interest)
represent the sample variance given
n=25 represent the sample size
Solution
The confidence interval for the true mean is given by :
(1)
The sample deviation would be
The degrees of freedom are given by:
The Confidence is 0.954 or 95.4%, the value of and
, assuming that we can use the normal distribution in order to find the quantile the critical value would be
The confidence interval would be
And the best option would be:
c. 1450 +/- 12