We know there are 4 suites the deck can be divided into, and two of the 4 are black. So you divide 2/4, and get 1/2. So the probability that a black card will be chosen is 1/2.
1,038/12= 86.5833333 86x12=1,032
1,039-1,032=7 left over So you’ll need 87 boxes
(-2,2)(2,-2)
slope = (-2 - 2) / (2 - (-2) = -4/4 = -1
as far as point slope form, there can be 2 answers...
y - y1 = m(x - x1)
slope(m) = -1
using points (-2,2)...x1 = -2 and y1 = 2
now we sub
y - 2 = -1(x - (-2) =
y - 2 = -1(x + 2) <== or could be written as y - 2 = - (x + 2)
y - y1 = m(x - x1)
slope(m) = -1
using points (2,-2)...x1 = 2 and y1 = -2
now we sub
y - (-2) = -1(x - 2) =
y + 2 = -1(x - 2) <== or can be written as y + 2 = - (x - 2)
either one of those answers is ur point slope form
Answer:
- B = 58°
- a = 6.6896
- c = 1.5915
Step-by-step explanation:
Given two angles and the side between them, the first step must be to find the value of the third angle, the one opposite the given side. It will be ...
B = 180° -A -C = 180° -109° -13° = 58°
Using this information and the Law of Sines, you can find the remaining sides.
a/sin(A) = b/sin(B) = c/sin(C)
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Then the missing sides are ...
a = b(sin(A)/sin(B)) = 6(sin(109°)/sin(58°)) ≈ 6.6896
c = b(sin(C)/sin(B)) = 6(sin(13°)/sin(58°)) ≈ 1.5915
The missing measures are ...
B = 58°
a = 6.6896
c = 1.5915
As long as you have a passing grade yes you can
