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3 years ago

This is the question

Mathematics

1 answer:

pishuonlain [190]3 years ago

4 0

Answer:

1st blank: Variable

2nd blank: one

Step-by-step explanation:

It should be:

To solve an equation, you must apply the variable to one side of the equation.

This makes sense to me, but I'm not 100% positive.

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Find the break-even point for the given cost and revenue equations. Round to the nearest whole unit. C = 20n + 134,000 R = 160n

Harman [31]

At break-even C = R so we have:-

20n + 134,000 = 160n

140n = 134,000

answer = 134,000 / 140 = 957

8 0

3 years ago

In a science class, 40% of the students received a grade of A, 30% received a grade of B, and 20% received a grade of C on a pro

8090 [49]

Answer:

30 students are in the science class and 3 students recieved a failing grade.

7 0

3 years ago

Read 2 more answers

Choose all that correctly solve for x.

Tamiku [17]

Answer:

Options: A, B, and C correctly solve for x.

Step-by-step explanation:

A).

$\frac{5}{2} x$ = $\frac{15}{2}$

Multiplying both sides by 2 gives;

5x = 15

x = 15 ÷ 5 = 3

∴ This option correctly solve for x.

B).

x + $\frac{7}{2}$ = 7

x = 7 - $\frac{7}{2}$ = $\frac{14}{2} -\frac{7}{2} = \frac{7}{2}$

∴ This option correctly solve for x.

C).

x + 3 = $\frac{21}{5}$

x = $\frac{21}{5} - \frac{15}{5} = \frac{6}{5}$

But the option give x as 5/6 hence this option does not correctly solve for x.

D).

5x = 11/2

x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10

But the option gives x as 10/11 so it does not correctly solve for x.

8 0

3 years ago

1/3 (12 - 24v) = -2(4v -2)

ANEK [815]

Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.

3 0

3 years ago

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0

oksian1 [2.3K]

<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

$\overline{x}\pm z^* SE$ (1)

, where $\overline{x}$ = sample mean

z* = critical value.

SE = standard error

and $SE=\dfrac{\sigma}{\sqrt{n}}$ , $\sigma$ = population standard deviation.

n= sample size.

As per given , we have

$\overline{x}=74.021$

$\sigma=0.001$

n= 15

It is known that ring diameter is normally distributed.

$SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199$

By z-table ,

The critical value for 95% confidence = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

$74.021\pm (2.576) (0.000258199)$ (using (1))

$74.021\pm 0.000665120624$

$74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)$ [Rounded to three decimal places]

∴ A 99% two-sided confidence interval on the true mean piston diameter = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

$74.021- (1.96) (0.000258199)$ (using (1))

$74.021- 0.00050607004=74.02049393\approx74.020$ [Rounded to three decimal places]

∴ A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0

3 years ago