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4 years ago

How can polygons be considered a subcategory of two-dimensional figures?

Mathematics

1 answer:

Greeley [361]4 years ago

6 0

Well, the polygon has at least three straight sides and angles, typically 5 or more

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Identify the quotient in the form a + bi. HELP ASAP PLEASE!!

Artist 52 [7]

Solving $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

Option A is correct.

Step-by-step explanation:

We need to find the result of $\frac{4-5i}{2+3i}$

We need to remove i from the denominator. For removing i Multiplying and dividing by 2-3i:

$\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}$

Solving:

$=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i*(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,i^2=-1\\=\frac{8-12i-10i+15(-1))}{4-9(-1)}\\=\frac{8-12i-10i-15}{4+9}\\=\frac{8-15-12i-10i}{13}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

5 0

3 years ago

Simplify the expression using positive exponents.<br>

Maksim231197 [3]

The answer is - 2x/3y

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4 years ago

What is 1. - ------- Of 40? - 10

raketka [301]

This is what you do. You multiply 1/10 and 40. Like this: 1/10 x 40/1

3 0

4 years ago

Graph y = - 1/2r-6 AND GIVE ME THE RIGHT ANSWER.

Nana76 [90]

Hello!

Are you in algebra?

Here is how to solve and graph.

First, look for the slope and y-intercept of your equation.

y = - 1/2r-6

The y intercept is, -6

The slope is -1/2

the variable r, is another way to represent x, as it is just a variable.

now that you have all that information, plot -6 on the graph, -6 should be on the y- axis.

from that point, move down one space and move right two space. complete this step multiple times.

Now please look at the photo, and Here's what the graph should look like.

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3 years ago

Solve the equation <br><img src="https://tex.z-dn.net/?f=2%20%5Csin%20%5E%7B3%7D%20%20x%20-%20%5Csin%20%5C%3A%20x%20%3D%200%20"

lyudmila [28]

Answer:

Step-by-step explanation:

$2 sin^3x-sin x=0\\sinx(2sin^2x-1)=0\\either~sin x=0,x=n\pi ,where ~n~is~an~integer.\\or~2sin ^2x-1=0\\or~1-2sin^2x=0\\cos 2x=0\\2x=(2n+1)\frac{\pi }{2} \\or~x=(2n+1)\frac{\pi }{4} ,where~n~is~an~integer.$

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3 years ago