m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
3
Step-by-step explanation:
In the Slope-Intercept Formula, <em>y</em><em> </em><em>=</em><em> </em><em>mx</em><em> </em><em>+</em><em> </em><em>b</em><em>,</em><em> </em><em>m</em><em> </em>is the <em>Rate</em><em> </em><em>of</em><em> </em><em>Change</em><em> </em>[<em>Slope</em>]. Anyway, starting from the <em>y-intercept</em><em> </em>of [0, 2], move 3 units <em>north</em><em> </em>over 1 unit <em>east</em><em>.</em><em> </em>That is called <em>rise</em><em>\</em><em>run</em><em> </em><em>→</em><em> </em>3\1 = 3.
I am joyous to assist you anytime.
-x ---------------- 1x
7y --------------- 12y
-12x^2 --------- 8x^2
a ----------------- -2a
6a^2------------ a^2
-5x^3 ---------- 15x^3
_____________________
you just have to match the terms which have the same power.
Hope it helps ^^
Answer:
3
Step-by-step explanation:
10/4 = 2 1/2
2 1/2 + 2/4 = 3
Answer:
this doesn't look fun.
Step-by-step explanation:
