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MakcuM [25]
3 years ago
8

Use algebra tiles to find the difference. Let one yellow tile equal +1 and one red tile equal –1. 8 – (–6)

Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

There is 10 white tiles, and shade 9 of them.

<u>One of the tiles are NOT shaded.</u>


SO, your answer will be.

<h2>=1 tile</h2>
Sauron [17]3 years ago
4 0

We draw 10 white tiles.

Then we shade in 9 of them.

We count the remaining tiles to get the answer, which is 1.

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Lyrx [107]

Let me fill in the statement reasoning for you:

Statement         |           Reasoning

∆ABC ~ ∆RST               Given

∆DEF ~ ∆RST                

∠A = ∠R, ∠D = ∠R         Definition of ~ ∆

∠C = ∠T, ∠F = ∠T          

∠A = ∠D,∠C = ∠F          Transitivity

∆ABC ~ ∆DEF                AA

7 0
3 years ago
Suppose you need to know an equation of the tangent plane to a surface S at the point P(4, 1, 3). You don't have an equation for
Harlamova29_29 [7]

Answer:

-30(x-4)  + 29 (y-1)  -12(z-3)  =  0

Step-by-step explanation:

You can find the perpendicular vector to both curves using the cross product  between them, and that will give you all the information you need to find the equation of the tangent plane to the surface S.

Let's find the parameter of each curve for the specific point.

For the first curve  notice that

r( 0 ) = (4,1,3)

And for the second curve notice that

r2(1) = (4,1,3)

Thus for the first curve we reach our point at t=0,    and for the second curve we reach our point at u = 1 .

Then we compute the tangent vector to our curves, and it would be given by the derivative so

r1'(t) = (2,-2t,-5+2t)     and at  t = 0    we have that  

r1'(0) = (2,0,-5)

Similarly

r2'(1)=(3+2(1) , 6(1)^2 ,2) = (5,6,2)

The the cross product between the two vectors would be

(5,6,2) \times (2,0,-5)  = (-30,29,-12)

Since (-30,29,-12) would be the perpendicular vector to the tangent plane and (4,1,3) would be a point of the tangent  then we would have that the equation of the tangent plane is given by

-30(x-4)  + 29 (y-1)  -12(z-3)  =  0

4 0
3 years ago
Assistance with polynomials
TiliK225 [7]
Should be the second one. 
4 0
3 years ago
What is the area of the figure please help the small section is messing me up​
Brrunno [24]

Answer:

177 sq ft

Step-by-step explanation:

Big square = 169

4+4 = 8

13-8 = 5•1.6 = 8

Little square = 8

169+8 =177

7 0
3 years ago
How do you find all the solutions to the equation 5x^2-27=2x^2+48 using the zero product property?
Dmitrij [34]
First, you have to get the equation equal to 0. To do that, you need to subtract the 2 x^{2} and 48 from the right side of the equation and put it on the left side. The new equation will read 
5 0
3 years ago
Read 2 more answers
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