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Paha777 [63]
2 years ago
14

Given the equation 8+ 9x = 89 Is x=9 a solution to the equation?

Mathematics
1 answer:
tamaranim1 [39]2 years ago
8 0

Answer:

X=9

Step-by-step explanation:

That is correct, 8 + 9(9) = 89

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Find tan(450-a), If <br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"
Inessa05 [86]

Answer:

tan(450-a)=5\sqrt{3}-8

Step-by-step explanation:

We know that:

tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

tan(450-a)=\frac{tan(450)-tan(a)}{1+tan(450)tan(a)}

Remember:

450°=360°+60°

and:

tan(a)=\frac{1}{2}

Thus:

tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\

Then:

tan(450-a)=5\sqrt{3}-8

4 0
2 years ago
1/6 is equal to what
Anastasy [175]

1/6 = 0.1666, the last number repeating to infinity, or a repeating decimal.

Hope helps!-Aparri

6 0
3 years ago
Read 2 more answers
According to the data, Vannessa mean quiz ...
damaskus [11]

Answer: x = 108

Given the below equation

x + 13 1/2 = 121 1/2

Firstly, we need to convert the mixed fraction into an improper fraction

\begin{gathered} x\text{ + 13}\frac{1}{2}\text{ = 121 }\frac{1}{2} \\ 13\frac{1}{2}\text{ = }\frac{(2\text{ x 13) + 1}}{2} \\ 13\text{ }\frac{1}{2}\text{ = }\frac{26\text{ + 1}}{2} \\ 13\frac{1}{2}\text{ = }\frac{27}{2} \\ 121\frac{1}{2}\text{ = }\frac{(2\text{ x 121) + 1}}{2} \\ 121\frac{1}{2}\text{ = }\frac{243}{2} \\ \text{Therefore, the new equation becomes} \\ x\text{ + }\frac{27}{2}\text{ = }\frac{243}{2} \\ \text{Isolate x} \\ x\text{ = }\frac{243}{2}\text{ - }\frac{27}{2} \\ \text{Common denominator = 2} \\ x=\text{ }\frac{243\text{ - 27}}{2} \\ x\text{ = }\frac{216}{2} \\ x\text{ = 108} \end{gathered}

8 0
1 year ago
Heyaaa, can you help me out? I'm not exactly sure how to go about solving this.​
scZoUnD [109]

Answer:

$48

Step-by-step explanation:

if youre paying 9.60 in tax and the tax is 20% you have to find out what 9.60 is 20% of

and 9.60 is 20% of 48

4 0
2 years ago
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Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a2 + b2 = c2, which in this iso
abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0
3 years ago
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