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slavikrds [6]
3 years ago
15

Please help me guys, I'll give brainliest Tysm !!

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Hello! :)

\large\boxed{ =7^{8}}

Use the exponential rule:

a^{b} * a^{c} = a^{b + c}

Use this property in this scenario:

7^{2} * 7^{6} = 7^{2 + 6}

Simplify:

= 7^{8}

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Translate the following phrase into an algebraic expression. Do not simplify. Use the variable names "x" or "y" to describe the
Rainbow [258]

Answer:

this would be 4x

Step-by-step explanation:

this is because when you carry over the dividend you have to divide it by 2 and assuming y is 8 the answer would be 4x

7 0
3 years ago
Simplify (8.3) 2.10.(6-1)​
vagabundo [1.1K]

Answer:

8 .3 \times 2.10.5

Step-by-step explanation:

Simplify 6 - 1 to 5.

8.3 \times 2.10 .5

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>3</u><u> </u><u>×</u><u> </u><u>2.10</u><u>.</u><u>5</u>

6 0
3 years ago
HELP &lt;3 Match the expressions with their solutions.
densk [106]

Answer:

1 ) sin 165°

2 ) cos 330°

3 ) Tan 157.5°

4 ) sin^2 157.5

Step-by-step explanation:

1 )

Given expression is  \sqrt{\frac{1-cos330}{2} }

We know that cos2x=1-2sinx^{2}

sinx^{2}=\frac{1-cos2x}{2}

(sinx/2)^2=\frac{1-cosx}{2}

So the first expression is sin (330/2)° =sin 165°

2 )

GIven expression is  1-2sin^2165

We know that cos2x=1-2sinx^{2}

So the result is cos 330°

3 )

Given expression is \frac{1-cos 315}{sin315}

We know that cos2x=1-2sinx^{2}

Also we know that sin2x = 2sinxcosx

So The numerator becomes 2sin^2x/2. and the denominator becomes as 2sinx/2cosx/2

\frac{2sin^2x/2}{2sinx/2cosx/2}=tanx/2

So the result is Tan 157.5°

4 )

Given expression is \frac{1-cos 315}{2}

We know that cos2x=1-2sinx^{2}

(sinx/2)^2=\frac{1-cosx}{2}

So the result is sin^2 157.5

6 0
4 years ago
An arithmetic sequence has a common difference of 5 and the 3rd term is 15. What is the 5th term?
trapecia [35]

Answer:

an=8n−14

Step-by-step explanation:

for an AP

where

a

1

=

the first term

d

=

the common difference

then we have

a

1

,

(

a

1

+

d

)

,

(

a

1

+

2

d

)

,

...

,

a

1

+

(

(

n

−

1

)

d

)

,

.

.

we are given the third term

10

=

a

1

+

2

d

−

−

(

1

)

and the fifth term

26

=

a

1

+

4

d

−

−

(

2

)

subtract

(

2

)

−

(

1

)

16

=

2

d

⇒

d

=

8

sub into

(

1

)

10

=

a

1

+

2

×

8

⇒

a

1

=

−

6

so the nth term

a

n

=

a

+

(

n

−

1

)

will be

a

n

=

−

6

+

8

(

n

−

1

)

a

n

=

8

n

−

14

3 0
3 years ago
After the fraction x plus 1 all over 2 minus the fraction x plus 2 all over 3 x have been combined using the Least Common Denomi
Ugo [173]
So in simplifying this functions that composed of fractional form and the lest common denominator of its is 6x. So based on my calculation by the used of the LCD of the functions, i came up with a numerator of 3x^2-x+2 by simplifying its numerator
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3 years ago
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