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seraphim [82]
3 years ago
8

Someone hep me please no one is helping me

Mathematics
1 answer:
laila [671]3 years ago
6 0

Answer:

the answer is 38 cm

Step-by-step explanation:

10+6+(6x3)+4=38 the 2 missing numbers are 2cm and 3cm

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Ruth decides to test the method of proportions and similar
olga nikolaevna [1]

Answer:

B.

Step-by-step explanation:

7 0
3 years ago
1.18. A fish tank has a base, B, with an area, in square inches, modeled by B(x) = 2x + 6x + 4.
Alekssandra [29.7K]

Answer:

The volume of fish tank is V(x)=2x^3+12x^2+22x+12

Step-by-step explanation:

Area of Base of fish tank = Length \times Breadth

We are given that A fish tank has a base, B, with an area, in square inches, modeled byB(x) = 2x^2 + 6x + 4.

So,  Length \times Breadth =2x^2 + 6x + 4.

Height of tank = x+3

Volume of tank = Length \times Breadth \times Height

So, Volume of tank =(2x^2 + 6x + 4)(x+3)

Volume of Tank =2x^3+6x^2+4x+6x^2+18x+12=2x^3+12x^2+22x+12

Hence The volume of fish tank is V(x)=2x^3+12x^2+22x+12

4 0
3 years ago
A triangle has side lengths of (1.2u+1.8v)(1.2u+1.8v) centimeters, (6.5u+8.7w)(6.5u+8.7w) centimeters, and (5.8w-6.9v)(5.8w−6.9v
Komok [63]

Answer:

7.7u - 5.1v + 14.5w

Step-by-step explanation:

Given length:

Side A = (1.2u+1.8v) centimeters,

Side B = (6.5u+8.7w) centimeters

Side C = (5.8w-6.9v) centimeters

Perimeter of a triangle = side A + side B + side C

= (1.2u+1.8v) + (6.5u+8.7w) + (5.8w-6.9v)

= 1.2u + 1.8v + 6.5u + 8.7w + 5.8w - 6.9v

Collect like terms

= 1.2u + 6.5u + 1.8v - 6.9v + 8.7w + 5.8w

= 7.7u - 5.1v + 14.5w

Therefore, the perimeter of the triangle is 7.7u - 5.1v + 14.5w

5 0
4 years ago
Please answer quickly! Several questions from Algebra 2, on a unit about Sequences and Series, most of these have to do with Ari
AnnyKZ [126]

The sum of the geometric series is 2199; option E.

  • The 36th term of the arithmetic series is -60.5 option C
  • The sum of the arithmetic series is 2547; option E
  • The missing geometric sequence are; 1.614375, 3.30946875, 6.7844109375. option E

<h3>Arithmetic and Geometric series</h3>

  • a1 = 1458
  • r = 1/3
  • a6 = 6

S6 = a(rⁿ - 1) / r -1

= 1468(1/3^6 - 1) / (1/3 - 1)

= 1468(0.00137174211248 - 1) / -2/3

= 1468(-0.9986282578875) / -0.66666666666666

= -1,465.98628257885 / -0.66666666666666

= 2198.97942386829

Approximately,

S6 = 2199

Arithmetic series

  • a36
  • a1 = 27
  • d = -5/2

Sn = n/2{2a + (n -1)d}

= 36/2 {2×27 + (36-1)-5/2}

= 18{54 + (35)-5/2}

= 18(54 + 175/2)

= 18(54 + 87.5)

= 18(141.5)

s36 = 2547

a36 = a + (n - 1) d

= 27 + (36 - 1)-5/2

= 27 + (35)-5/2

=27 + -175/2

= 27 - 87.5

= -60.5

S20 = n/2{2a + (n -1)d}

= 20/2{2×27 + (20-1)-5}

= 10(54 + (19)-5)

= 10{54 + (-95)}

= 10(54-95)

= 10(-41)

s20 = -410

Missing terms of the geometric sequence:

nth term = ar^n-1

448/135 = 63/80×r^(6-1)

448/135 = 63/80×r^5

r^5 = 448/135 ÷ 63/80

= 448/135 × 80/63

= 35,840/8,505

r = 5√35,840/5√8505

= 946.57/461.11

r = 2.05

Second term = a×r

= 63/80×2.05

= 1.614375

Third term = ar²

= 63/80×2.05²

= 63/80×4.2025

= 3.30946875

Fourth term = 63/80 × 2.05³

= 63/80×8.615125

= 6.7844109375

Therefore, none of these are correct

Learn more about sum of geometric series:

brainly.com/question/24643676

#SPJ1

4 0
2 years ago
Which three angles with the given measures can be used to construct at least one triangle? 40°,20°,40° 45°,45°,45° 23°,23°,134°
goldenfox [79]
D is the answer  :) hope this helped
3 0
3 years ago
Read 2 more answers
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