Remainder of question:
Find the probability distribution of x
Answer:
The random variable x is defined as: X = {0, 1, 2, 3, 4}
The probability distribution of X:
P(X = 0) = 0.656
P(X = 1) = 0.2916
P(X= 2) = 0.0486
P(X=3) = 0.0036
P(X = 4) = 0.0001
Step-by-step explanation:
Sample size, n = 4
Random variable, X = {0, 1, 2, 3, 4}
10% (0.1) of the homeowners are insured against earthquake, p = 0.1
Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1
q = 0.9
Probability distribution of x,
Answer: The mean number of checks written per day 
Standard deviation
Variance
Step-by-step explanation:
Given : The total number of checks wrote by person in a year = 126
Assume that the year is not a leap year.
Then 1 year = 365 days
Let the random variable x represent the number of checks he wrote in one day.
Then , the mean number of checks wrote by person each days id=s given by :-
Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. 
Standard deviation : 
Answer:
7,620,650
Step-by-step explanation:
___________
Answer:
(a) How many are there to select 2 pairs of gloves?
10 ways
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
130 ways
Step-by-step explanation:
We solve the above questions using Combination
Combination = C(n, r) = nCr
= n!/n! ×(n - r)!
(a) How many are there to select 2 pairs of gloves?
We have 5 pairs of gloves. Therefore, the number of ways to select 2 gloves =5C2
= 5!/2! × (5 - 2)!
= 5!/2! × 3!
= 5 × 4 × 3 × 2 × 1/(2 × 1) × (3 × 2 × 1)!
= 10 ways.
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
We are told to select 4 gloves out of the 10 gloves = 10C4
We have 5 pairs, we need to make sure that two out of the selected 4 make a pair = 5 × 2⁴
= 80
Hence,
10C4 - 5C4
= [10!/4! × (10 - 4)!] - 80
= 210 - 80
= 130 ways
