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taurus [48]
3 years ago
13

Make a sketch of a linear relationship with slope 3 that is not a proportional relationship show how you know hay slope is 3 wri

te an equation for the line
Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

Answer:

A proportional relationship is something like:

y = k*x

Where k is the constant of proportionality

And a linear relationship is something like:

y = a*x + b

Is easy to see that if:

a = k, and b = 0, this would be a proportional relationship.

Then if we want to have a slope equal to 3, but this must not be a proportional relationship, we must only have b different than 0.

This could be something like:

y = 3*x + 1

The graph of this is:

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please help!!!! 10 points!!!!! I’ve been trying to figure this out for 45 mins now and still haven’t been able to :(
7nadin3 [17]
What does this mean I’m confused
7 0
3 years ago
Verify the following identity. <br><br> <img src="https://tex.z-dn.net/?f=-%5Cfrac%7Bcos%283x%29%2Bcos%285x%29%7D%7Bsin%283x%29-
kogti [31]

Recall the angle sum identities:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

sin(a + b) = sin(a) cos(b) + sin(b) cos(a)

sin(a - b) = sin(a) cos(b) - sin(b) cos(a)

Notice that adding the first two together, and subtract the last from the third, we get two more identities:

cos(a + b) + cos(a - b) = 2 cos(a) cos(b)

sin(a + b) + sin(a - b) = 2 sin(b) cos(a)

Let a = 4x and b = x. Then

cos(5x) + cos(3x) = 2 cos(4x) cos(x)

sin(5x) - sin(3x) = 2 sin(x) cos(4x)

Now,

-\dfrac{\cos(3x)+\cos(5x)}{\sin(3x)-\sin(5x)}=\dfrac{\cos(5x)+\cos(3x)}{\sin(5x)-\sin(3x)}=\dfrac{2\cos(4x)\cos x}{2\sin x\cos(4x)}=\dfrac{\cos x}{\sin x}=\cot x

as required.

4 0
4 years ago
Anser true or false:
kakasveta [241]

Answer:

true

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve the triangle. Round side measure to the nearest tenth and angle measures to the nearest degree.
shutvik [7]
First calculate the missing angle \alpha. By knowing all angles in triangle have a sum of 180°.

\alpha=180-(\gamma+\beta)
\alpha=180-(90+49)=\boxed{41}

Now we required to use angle functions in a right triangle. The cosine of \beta is equal to the relation of side a and hypotenuse c.

Now we solve this for hypotenuse.

\cos(\beta)=\frac{a}{c}

c=\frac{a}{\cos(\beta)}

Now put in the numbers.

c=\frac{9}{\cos(49)}\approx\boxed{13.7}

So we know the length of hypotenuse and length of side a therefore side b can be calculated using Pythagorean theorem: c^2=a^2+b^2.

Solve for side b.

c^2=a^2+b^2

b=\sqrt{c^2-a^2}

b=\sqrt{13.7^2-9^2}\approx\boxed{9.7}

So there you go. If you have any questions feel free to ask.

r3t40
6 0
4 years ago
Enter the unknown value that makes this statement true.<br><br><br> 35 is *Box* % of 70
IgorC [24]

Answer:

50%

Step-by-step explanation:

35x2=70

4 0
3 years ago
Read 2 more answers
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