Answer:
Number of bacteria when t = 10 min is 3,000
Step-by-step explanation:
Given:
Number of bacteria in a culture by equation
Q(t) = 2(729^t)
Value of t = 10 min = 10 / 60 = 0.1667 hour
where t is number of hours
Find:
Number of bacteria when t = 0.1667 hour
Computation:
Given equation
Q(t) = 2(729^t)
Put t = 0.1667
Q(10) = 2(729⁰'¹⁶⁶⁷)
We know that;
a⁰ = 1
So,
Q(0.1667) = 2(729⁰)
Q(0.1667) = 3
Number of bacteria when t = 0 is 3,000
Answer:
149
Step-by-step explanation:
There is a common difference between consecutive terms in the sequence.
5 - 2 = 8 - 5 = 11 - 8 = 14 - 11 = 3
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 2 and d = 3 , thus
a₅₀ = 2 + (49 × 3) = 2 + 147 = 149
On the X side it’s +1
Hopefully this helps
Step-by-step explanation:
8x² + 8x - 21 = 0
8(x² + x) - 21 = 0
8(x + 0.5)² - 23 = 0
8(x + 0.5)² = 23
(x + 0.5)² = 23/8.
