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3 years ago

Need some help on my math

Mathematics

1 answer:

SashulF [63]3 years ago

7 0

Answer:

2 and 9/10

Step-by-step explanation:

3 1/2 as an improper fraction is 7/2

7/2-3/5=2 9/10

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The equation of a circle is (x-1)^2 +(y-2)^2=4. What is the center of the circle and what is the radius of the circle?

Virty [35]

Answer:

Step-by-step explanation:

(x-1)²+(y-2)² =4 compare the given equation with the general one

(x-h)² +(y-k)² =r², where (h, k) are coordinates of the center and r is radius

so center is at ( 1, 2) and radius is 2

8 0

3 years ago

Owen used these steps to solve the equation 4x+7=1+2(2x+3). Which choice describes the meaning of his result, 7=7?

ivanzaharov [21]

Answer:

Option D. All values of x make the equation true

Step-by-step explanation:

<u><em>The options of the question are</em></u>

a.The result is not correct because Step 2 has an error.

b.The solution is x=7.

c.No values of x make the equation true.

d.All values of x make the equation true

we have the equation

$4x+7=1+2(2x+3)$

solve for x

Apply distributive property right side

$4x+7=1+4x+6$

Combine like terms

$4x+7=4x+7$

subtract 4x both sides

$7=7$

The equation has infinity solutions

.All values of x make the equation true

6 0

3 years ago

Find the measure of

Butoxors [25]

Step-by-step explanation:

angles a,f,g form a triangle

sum of angles in ∆ = 33 + 112+ a = 180

145 + a = 180

a = 35°

7 0

2 years ago

Someone knows this? if you know it help me please and thank you also show your work pleaseee

Taya2010 [7]

With math always you photo math get a calculator help and not a human and then click explain work

5 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago