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Gnoma [55]
3 years ago
13

6 Gallons and 3 quarts = ________ quarts?

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

Answer: 27 quarts

Step-by-step explanation:

6 gallons is 24 quarts. Add the 3 to get 27. Formula: Gx4= Q

6x4=24 Plus the 3 extra= 27 quarts Hope this Helps uwu

elixir [45]3 years ago
3 0

Answer: is 27 quarts

Step-by-step explanation:

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a park is shaped like a rectangle with a length 11 times its width w. what is a simplified expression for the distance between o
garik1379 [7]
Width = w
length = 11w
Pythagoras theorem
a^2 + b^2 = c^2
Let's say the width is a, the length is b, and the distance between corners (call it d) is c
w^2 + 11w^2 = d^2
Collect like terms,
12w^2 = d^2
Simply
12w = d
4 0
3 years ago
Read 2 more answers
ticket sales for a local concert totaled $101,244 yesterday. After the ticket window closed today, the cashiers counted 968 tick
STALIN [3.7K]

The cost of one concert ticket is approximately  $148.59.

The tickets sales for the local sales is totalled $101, 244 yesterday.

ticket sales yesterday = $101244

He sold 968 tickets with a two-days total of $143, 836 (both yesterday and today)

The cost of one ticket can be calculated below:

cost of one ticket = 143,836 / 968

cost of one ticket = 148.590909091

cost of one ticket ≈ $ 148.59

read more: brainly.com/question/15471320?referrer=searchResults

3 0
2 years ago
 helloo , i need help with this problem it says write this number (797,000,000,000+ 619,000,000+132)in standard form, please h
inysia [295]

Okay its 797,619,000,132

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4 0
2 years ago
Which equation can be used to represent the statement?
AfilCa [17]

Answer:

I would say 16=1.2n+(negative 8) because they are in the same order as it was spelled in words and not numbers that's how I know that it could be 16=1.2n+(negative 8).

Step-by-step explanation:

8 0
3 years ago
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5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

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Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
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