he will be reimbursed 137.26 dollars for two days
The answer is A. one of the zeros is x = -1
I believe in standard form this would be 31/2 + 27i/2
So the function is

the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .
What are what are you talking abt