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Ksju [112]
3 years ago
10

Anna’s cell phone plan charges her $30 per month plus a $150 one-time activation fee. Evelyn’s cell phone plan charges her $20 p

er month, plus a $450 one-time activation fee. After how many months are the costs for the girls’ cell phone plans the same?
Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Given:

Anna’s cell phone plan charges her $30 per month plus a $150 one-time activation fee.

Evelyn’s cell phone plan charges her $20 per month, plus a $450 one-time activation fee.

To find:

The number of months after which the costs for the girls’ cell phone plans the same.

Solution:

Let x be the number of months.

Total cost = Fixed cost + Variable cost

According to the question, cost equation for Anna’s cell phone is

y=150+30x           ...(i)

Cost equation for Evelyn's cell phone is

y=450+20x         ...(ii)

Equate (i) and (ii) to find the time after which the costs for the girls’ cell phone plans the same.

150+30x=450+20x

30x-20x=450-150

10x=300

Divide both sides by 10.

x=\dfrac{300}{10}

x=30

Therefore, the costs for the girls’ cell phone plans the same after 10 months.

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xenn [34]

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

\texttt{ }

<em>Let:</em>

<em>Volumes of 2% Solution = x</em>

<em>Volumes of 10% Solution = y</em>

\texttt{ }

<em>Total Volume = 10 ml</em>

\boxed{x + y = 10} → <em>Equation 1</em>

\texttt{ }

<em>The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution</em>.

2 \% x + 10 \% y = 6 \% (10)

2x + 10y = 6(10)

\boxed{x + 5y = 30} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1 - Equation 2:</em>

( x + y ) - ( x + 5y ) = 10 - 30

-4y = -20

y = -20 \div -4

y = 5 \texttt{ ml}

\texttt{ }

x + y = 10

x + 5 = 10

x = 5 \texttt{ ml}

\texttt{ }

<h2>Conclusion:</h2>

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

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AlexFokin [52]

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4 0
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Yuliya22 [10]

Answer:

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Step-by-step explanation:

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The question is asking you if it is true that 11 - 4 is greater than 4 + 2. To get an answer, Solve both of the problems.

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