Answer: The answer is in the attachment below!
the first one is -6, 8 second is 0,8!
If you tell me the question I'd be happy to answer. c:
11 plus what number equals 16 in order to complete your problem.
Answer:
Area of the other polygon = 4 in.²
Step-by-step explanation:
Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon
Let "x" represent the area of the smaller polygon
Thus, we have:
100/x = 20²/4²
100/x = 400/16
100/x = 25
Cross multiply
25x = 100
Divide both sides by 25
25x/25 = 100/25
x = 4
Area of the other polygon = 4 in.²
Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
