Answer:
Occurrence and accumulation in time of new mutations in each of the separated populations. This leads to a gradual differentiation.
Explanation:
Allopatric speciation consists of the geographic separation of an original population so that it can give place to two or more new geographically isolated populations. These separations might be due to migration, extinction of geographically intermediate populations, or geological events. In this speciation, some barriers impede genetic interchange, or genetic flux, as the two new populations that are separated can not get together and mate anymore. These barriers might be geographical or ecological.
The process of allopatric speciation involves different steps:
- The emergence of the barrier,
- Interruption in the genetic interchange,
- The occurrence of new mutations and their accumulation in time in each population. Slow and gradual differentiation,
- Genetic divergence by natural selection and reproductive isolation, which makes it impossible for the two groups to cross even if the barrier disappears,
- Prezigotic isolation mechanisms favored by selection once it occurs a secondary contact between the new species in formation.
Answer:
Hold up it is long
Explanation:
Instead, its purpose is to complete water and electrolyte (minerals found naturally in the body, such as potassium, calcium, sodium, and magnesium) absorption begun by the small intestine. Those components of food that are not needed or cannot be absorbed are excreted from the colon in stool.
B - A human gene inserted into a plasmid
Answer:
Florida because is always hot and fun
The reason this is so different is because those that are carriers (1 in 20) are heterozygous and to have a child with CF, they have to have a child with another carrier and then have the unlucky occurrence that their child will end up homozygous recessive.
So, 2 parents are Cc
C= normal CFTR (the gene at question here - Cystic Fibrosis Transmembrane Receptor)
c = mutated CFTR
Cross: Cc x Cc
You get: CC (1); Cc (2) and cc (1)....there is only a 0.25 chance that each time you have a child that it will be diseased (cc). Highest chance that the child is a carrier (Cc - 0.50) and similar low chance to no longer carry the recessive damaged allele (CC - 0.25)
