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3 years ago

Help me with this its super hard

Mathematics

1 answer:

Andreyy893 years ago

5 0

Answer:

240

Step-by-step explanation:

Because you have to do length times with times height

12 times 10 times 2= 240

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Write the equation of the line that passes through the point (-2,7)and has a slope of -5

swat32

Answer:

y = -2x - 3

Step-by-step explanation:

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3 years ago

Theres a pic need asap!!!

miskamm [114]

Answer:

Domain: [-1,3)

Range: (-5,3]

Step-by-step explanation:

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3 years ago

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Just need to know how to solve

daser333 [38]

Answer:

so where the points are on the triangles is where you would go side to side and up and down

Step-by-step explanation:

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3 years ago

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Solve 5.7y - 3.9y I is not smart lolz

denpristay [2]

5.7 of anything minus 3.9 of the same thing leaves 1.8 of them.

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4 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago