Answer:
a) (iii) ANOVA
b) The ANOVA test is more powerful than the t test when we want to compare group of means.
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
If we assume that we have
groups and on each group from
we have
individuals on each group we can define the following formulas of variation:



And we have this property

Solution to the problem
Part a
(i) confidence interval
False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.
(ii) t-test
Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.
(iii) ANOVA
This one is the best method when we want to compare more than 1 group of means.
(iv) Chi square
False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.
Part b
The ANOVA test is more powerful than the t test when we want to compare group of means.
No, it does not. 65-(45-20) is equal to 40, because you subtract 45-20 before because of the parentheses. When you do that, you get 25 then subtract 65-25, then get 40. Then, if you subtract 65-45 first and get 25, then subtract 25-20, you'll get 5.
Given:
The number of 100.
To find:
The given number as an exponential expression with 10 as the base.
Solution:
We have,
Given number = 100
It can be written as

![[\because a^m\cdot a^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Em%5Ccdot%20a%5En%3Da%5E%7Bm%2Bn%7D%5D)

Here, base is 10 and exponent is 2.
Therefore, the given number can be written as
.
Answer:
85
Step-by-step explanation:
60+60+70+80+85 = 355
355/5 = 71
26 for ad and bd 13 I believe