The correct answer is A) -34. Hope this helps.
Any quadrilateral which can be inscribed in a circle, is called a cyclic quadrilateral.
The main theorem about these quadrilaterals is the following:
In any cyclic quadrilateral, the sum of the measures of the opposite angles is 180°.
This means, m(∠S)+m(∠Q) =180°,
thus
(7x-2)+(5x+14)=180
12x+12=180
12x=168
x=168/12=14
Thus the measures of angles Q and S are respectively:
7x-2 = 7*14-2=96 (degrees) and
5x+14=5*14+14=6*14=84 (degrees)
Answer: D
Answer:
m=(-6,6)
Step-by-step explanation:
m^2 -36 = 0
Reorder the terms:
-36 + m^2 = 0
Solving for variable 'm'.
Add '36' to each side of the equation.
-36 + 36 + m^2 = 0 + 36
Combine like terms: -36 + 36 = 0
0 + m^2 = 0 + 36
m^2 = 0 + 36
Combine like terms: 0 + 36 = 36
m^2 = 36
Simplifying
m^2 = 36
Take the square root of each side:
√m^2=+/-√36
m=(+/-)6
m = {-6, 6}
Answer:
If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.
Step-by-step explanation:
AB=x
BC = 2x + 2BC=2x+2
AC =14AC=14
Required
Determine x, AB and BC.
Since B is between A and C;
AB + BC = ACAB+BC=AC
Substitute x for AB; 2x + 2 for BC and 14 for AC
x + 2x + 2 = 14x+2x+2=14
3x + 2 = 143x+2=14
Collect Like Terms
3x = 14 - 23x=14−2
3x = 123x=12 '
x = \frac{12}{3}x=
3
12
x = 4x=4
Substitute 4 for x in
AB = xAB=x
BC = 2x + 2BC=2x+2
AB = 4AB=4
BC = 2(4) + 2BC=2(4)+2
BC = 8 + 2BC=8+2
BC = 10BC=10
