Answer:
the surface area of the square pyramid is 576.66 cm^2
Step-by-step explanation:
The computation of the surface area of square pyramid is given below:
A = a^2 + 2a × √a^2 ÷ √4 + √h^2
where
a = 12 cm
h = 17 cm
Now put the value of a and h in the above formula
= 12^2 + 2(12) × √12^2 ÷ √4 + √17^2
= 576.66 cm^2
hence, the surface area of the square pyramid is 576.66 cm^2
Answer:
i don't really understand what you are asking me
Step-by-step explanation:
Let's start with a picture.
We see RST is smaller, and BC is parallel to but in the opposite direction to its corresponding segment ST. Both have slope -1.
If we look at the difference of points (technically called vectors but we don't have to go there) we get
C-B=(-2,2)
T-S=(1,-1)
Without further calculation we can see T-S is half the length of C-B.
The problem asks for a dilation followed by a reflection. We know the dilation scale is k=1/2 because the new triangle is half the size.
After dilation we get A'B'C':
A'(3,2), B'(-1,0), C'(-2,1)
We see now we need a reflection that flips the coordinates x and y. That's the +45° line through the origin, namely y=x.
Answer: k=1/2, y=x
