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solniwko [45]
3 years ago
7

Create a dictionary that maps a fruit name to its color. Both the keys and the values should be stored as strings. Include only

the following three entries in the dictionary: apple (red), orange (orange), and banana (yellow). Store the dictionary in a variable named fruit_dictionary.
Computers and Technology
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

Written in Python:

fruit_dictionary = {}

fruit_dictionary = {'apple': 'red', 'orange': 'orange', 'banana': 'yellow'}

Explanation:

First (although, not necessary), we create an empty dictionary named fruit_dictionary on line 1

Next, we populate the dictionary using the following syntax:

{key-1:value-1, key-2:value-2,......,key-n:value-n}

In this case, the entry would be:

{'apple': 'red',

'orange': 'orange',

'banana': 'yellow'}

The items on the first column (i.e. apple, orange and banana) are the keys while the items on the second (i.e. red, orange and yellow) are the values of the dictionary

To print the items in the dictionary, you can add  the following line of code:

<em>print(fruit_dictionary.items()) </em>

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Using the program below, explain what the output will be at LINE A. 1 #include 2#include 3#include 4 5 int value - 128; 6 7 int
slega [8]

Answer:

This is the complete correct program:

#include <stdio.h>

#include<sys/types.h>

#include<unistd.h>

int value = 128;

int main()

{

  pid_t pid;

  pid=fork();

  if (pid==0) /* child process */

  {

  value +=8;

  return 0; }

  else if (pid > 0) {/* parent process */

 wait (NULL);

 printf ("PARENT: value =%d\n" ,value); /* LINEA */

 return 0;

}

}

The output of the LINE A is:

PARENT: value = 128

Explanation:

The fork() function used in the program creates a new process and this process is the child process. The child process is same as the original process having its own address space or memory.

In the child process the value of pid is 0. So the if condition checks if pid==0. Then the child process adds 8 to the value of its variable according to the following statement  

value +=8;

Now the original process has value = 128. In else if part the parents process has the value of pid greater than zero and this portion of the program is of the parent process :

else if (pid > 0)

{ wait (NULL);

printf ("PARENT: value =%d\n" ,value);

return 0; }

So the value 128 is printed at the end in the output.

wait(NULL) is used to wait for the child process to terminate so the parent process waits untill child process completes.

So the conclusion is that even if the value of the variable pid is changed in the child process but it will not affect the value in the variable of the parent process.

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3 years ago
(a) Store last 7 digits of your student ID in a vector (7 element row or column vector). Write a MATLAB code which creates a 7x7
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Answer:

MATLAB code explained below with appropriate comments for better understanding

Explanation:

clc

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A = zeros(7);

for i=1:7

 

A(i,i)= ID(i);

 

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disp(A);

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disp(B);

fprintf('Both A and B are same\n');

%(b)

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fprintf('A(6,6) is even\n');

else

fprintf('A(6,6) is odd\n');

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%(c)

if(A(3,3)>0)

fprintf('A(3,3) is positive\n');

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fprintf('\nRequired series : ');

n = 35;

while n>=0

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if(n>0)

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n = input('\nInput an integer : ');

fprintf('%i! = ',n);

F = 1;

while n>1

F = F * n;

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fprintf('%i\n',F);

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clear all

x = [3 7 2 1];

y = [4 3 9 1];

A = 0;

C = x(1);

for i=1:length(x)

A = A + x(i)*y(i);

B(i) = x(i)/y(i);

if(min(x(i),y(i))<C)

C = min(x(i),y(i));

end

end

C = 1/C;

fprintf('\nA = %i\n',A);

fprintf('B = ');

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fprintf('C = %0.5g\n',C);

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maxA = A(1);

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i = 2;

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1 0 0 0 0 0 0

0 2 0 0 0 0 0

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0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

B =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

Both A and B are same

A(6,6) is even

A(3,3) is positive

Required series : 35, 30, 25, 20, 15, 10, 5, 0

Input an integer : 6

6! = 720

A = 52

B = 0.7500 2.3333 0.2222 1.0000

C = 1

A = 25 14 7 10 13 17 10 17 19 9

maxA = 25

minA = 7

>>

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