maintenance is the answer
It is called Windows Explorer referred as explorer.exe<span />
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
Answer:
dax and dear god, also my heart hurts
Explanation:
they are great so is he u should listen to him
Answer:
The correct answer will be "Project Gutenberg".
Explanation:
- Project Gutenberg continues to obtain lots of requests for authorization for using printed books, pictures, as well as derivatives from eBooks. Perhaps some applications should not be produced, because authorization would be included in the objects provided (as well as for professional usages).
- You can copy, hand it over, or m actually-use it underneath the provisions including its license that was included in the ebook.
So that the above is the right answer.
