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Katena32 [7]
3 years ago
15

Which chemical equation is balanced?

Mathematics
2 answers:
hammer [34]3 years ago
6 0

Step-by-step explanation:

CH4 + 2O2 →2H2O + CO2

the answer

irakobra [83]3 years ago
5 0

Answer:

The balanced chemical equation of the given reaction are;

b.CH4 + 202-> 2H20 + CO2

Step-by-step explanation:

C=C

H4=2H2

2O2=O2+2O(2O2)

I Think it helps you.

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Amy invites 800 people to her pool
antiseptic1488 [7]

Answer:

400

Step-by-step explanation:

4 0
2 years ago
I need to find the parent function and compare and contrast the domain and range of the parent function.
denpristay [2]
The parent function is f(x) = x^3 with domain = all real numbers and range = all real numbers.

The given function is f(x) = x^3 - 2 with domain = all real numbers and range = all real numbers.
8 0
3 years ago
Can you please show working out for $4,000 at 3% for 4 years
dedylja [7]
100\%+3\%=103\%\\\\p\%=\dfrac{p}{100}\to103\%=\dfrac{103}{100}=1.03\\\\\$4,000\cdot1.03^4=\$4,679.43
5 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Find the y-intercept of the line on the graph.
BARSIC [14]
It's a little hard to see, but I'm almost positive the y intercept is -1.
 
Remember, the y intercept is wherever the line intercepts in the y axis 0.

Good luck my man.
5 0
3 years ago
Read 2 more answers
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