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madreJ [45]
3 years ago
13

Jordan can build a birdhouse in 2 hours. If it takes her sister 3 hours to build a birdhouse, how long will it take them to buil

d a birdhouse together?
Mathematics
2 answers:
miskamm [114]3 years ago
3 0
To find the total work of two people at different speeds, we need to find a common speed limit to both.

In this case, Jordan can build a birdhouse in 2 hours so her speed is 1/2 birdhouse per hour.

For the sister, it takes 3 hours to build a birdhouse so her speed is 1/3 birdhouse per hour.

To find what they can do in one hour: \frac{1}{3} + \frac {1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6}

To find how long does it take to build a birdhouse: \frac{ \frac{5}{6}}{1} = \frac{1}{x}

Set the denominators equal: \frac{\frac{5}{6}x}{x} = \frac{1}{x}

Remove the denominators and solve: \frac{5x}{6} = 1

Once again set the denominators equal: \frac{5x}{6} = \frac{6}{6}

Remove the denominators and solve for x: 5x = 6  \\ \\ x = \frac{6}{5}

6/5 hours is equal to 72 minutes.
N76 [4]3 years ago
3 0

Answer:

if you came on here to find the answer for the A-Beka Algebra 1 quiz 36 for this question the answer is 1 1/5hr. or 1hr.12min.

Step-by-step explanation:

1. B. Cross multiply

2. D. 1

3. B. proportion

4. A. 4a-2/8a-a^2

5. a=2

6. c=0,6

7. 150ft (or just) 150

8. 1 1/5hr. (OR) 1hr.12min.


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How many more students arrive by school bus than by car?
sp2606 [1]

Answer:

125 more students arrive buy school bus than by car

Step-by-step explanation:

20% + 25% + 15% = 60%

Bus

100 - 60 = 40% ( bus = 40%)

40% = 0.4

0.4 × 500 = 200 (200 students get to school by the school bus)

Car

15% = 0.15

0.15 × 500 =

car = 75 (75 students get to school by car)

difference

200 - 75 = 125 students (125 more students get to school on the school bus then by a car)

8 0
2 years ago
The table shows the outputs y, for different inputs ,x
faust18 [17]

Part A: Yes, the data represent a function. The definition of a function is a relation in which no value of x will have two different values of y.

(Every time you plug in 3 as x, you will always get 4 as y; it's ok if you plug in 3 and 5 as x and get the same y, you just can't get two different y's for one x; sorry, it is pretty confusing). None of the numbers in the table repeat, so we can safely say that the relation is a function.

Part B: All we have to do is plug in 11 for x in the function given to find the answer:

In the table, y = 8 when x = 11, but in the function given, y = 34 when x = 11, so the function given is greater.

Part C: To find the answer to C, just plug in 99 for f(x), as it tells you to do:

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3 years ago
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Answer:

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mel-nik [20]

Answer:

C

Step-by-step explanation:

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