The quadratic formula is above.
You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3
Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a
E.) 15/53
F.) 15/53
G.) 18/53
H.) 12/53
Okay so the y is in absolute value, which means the number could be a negative and the absolute value would make is a positive.
since the sign is greater than, with no equal to underneath it, than the answer cant be 3 or -3.
the number has to total to be larger than 3. again, since the absolute value turns the negatives into positives, then -4 is an acceptable answer. so the absolute value line should look like the above (please excuse the terrible look). I simplified it to the two numbers that start the equation. the two circle are open circles because the sign does not include an equal sign under it. you draw the arrows on either side of the two numbers because any answer beyond those arrows fits in with the equation
| 4 |
| 184728 |
| -4.5829492994929492949572728 |
did that answer the problem?
